Reputation: 57
I started writing a simple calculator in Python. I noticed that the last lines of code that print the equation's result are repeated.
Can I write a function that takes the operator as input and then prints the result with just one line of code?
I imagine it would be something like this:
def result(num1, num2, operator):
print((str(num1)) + " " + str(operator) + " " + str(num2) + " = " + str(num1 **insert operator to compute equation** num2))
What I have currently:
num1 = float(input("Enter first number: "))
op = None
while op not in ("-", "+", "*", "/"):
op = input("Enter operator (-, +, *, /): ")
num2 = float(input("Enter second number: "))
if op == "-":
print((str(num1)) + " " + str(op) + " " + str(num2) + " = " + str(num1 - num2))
elif op == "+":
print((str(num1)) + " " + str(op) + " " + str(num2) + " = " + str(num1 + num2))
elif op == "*":
print((str(num1)) + " " + str(op) + " " + str(num2) + " = " + str(num1 * num2))
elif op == "/":
print((str(num1)) + " " + str(op) + " " + str(num2) + " = " + str(num1 / num2))
Upvotes: 2
Views: 1821
Reputation: 1045
I would use this method to keep it simple yet powerful.
eval
with the expression: The eval()
function evaluates the specified expression, if the expression is a legal Python statement, it will be executed.first = float(input("Enter the first number: "))
second = float(input("Enter second number: "))
operator = str(input("Enter operator: "))
# add checks for the operator
allowed_ops = ["+", "-", "*", "/"]
if operator not in allowed_ops:
raise Exception(f"Operator {operator} not allowed. Allowed operators are '{', '.join(allowed_ops)}'.")
# execute the expression
result = eval(f"{first} {operator} {second}")
print(result)
Upvotes: 2
Reputation: 7
number1 = int(input("pick a number "))
number2 = int (input("pick another number "))
def addition(number1,number2):
sum = (number1 + number2)
return sum
sum = addition(number1,number2)
print(sum)
def multiplication(number1,number2):
product = (number1 * number2)
return product
product = multiplication(number1,number2)
print(product)
def devision(number1,number2):
quotient = (number1 / number2)
return quotient
quotient = devision(number1,number2)
print(quotient)
def subtraction(number1,number2):
remander = (number1 - number2)
return remander
remander = subtraction(number1,number2)
print(remander)
Upvotes: -2
Reputation: 9
print('''
1. +
2. -
3. *
4. /
5. exit
''')
while True:
op = input("please choice the operation? ")
num1 = float(input("please insert first number? "))
num2 = float(input("please insert second number? "))
if op == "+":
result = (num1 + num2)
print("result is:", result)
elif op == "-":
result = (num1 - num2)
print("result is:", result)
elif op == "*":
result = (num1 * num2)
print("result is:", result)
elif op == "/":
result = (num1 / num2)
print("result is:", result)
elif op == "exit":
break
Upvotes: 0
Reputation: 10799
You might try using a dictionary to map strings (operators) to function objects:
from operator import add, sub, mul, floordiv
operations = {
"+": add,
"-": sub,
"*": mul,
"/": floordiv
}
a = float(input("Enter first number: "))
while (op := input("Enter operator: ")) not in operations: pass
# 'operation' is one of the four functions - the one 'op' mapped to.
operation = operations[op]
b = float(input("Enter second number: "))
# perform whatever operation 'op' mapped to.
result = operation(a, b)
print(f"{a} {op} {b} = {result}")
In this case, add
, sub
, mul
and floordiv
are the function objects, each of which take two parameters, and return a number.
Upvotes: 4