Reputation: 51
I'm on the 8th chapter (Methods, Constructors, and Fields) of my Java methods book and I'm having a problem with one of my exercises.
The provided code is Temperature.java
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.text.DecimalFormat;
public class Temperature extends JApplet
implements ActionListener {
private JTextField displayF, displayC;
private static DecimalFormat displayFormat = new DecimalFormat("0.0");
public void init() {
Container c = getContentPane();
c.setBackground(Color.white);
c.setLayout(new GridLayout(2, 2, 10, 0));
c.add(new JLabel(" Fahrenheit:"));
c.add(new JLabel(" Celsius:"));
displayF = new JTextField(6);
displayF.setBackground(Color.yellow);
displayF.addActionListener(this);
c.add(displayF);
displayC = new JTextField(6);
displayC.setBackground(Color.yellow);
displayC.addActionListener(this);
c.add(displayC);
}
public void actionPerformed(ActionEvent e) {
String s;
double degrees;
FCConverter fc = new FCConverter();
if ((JTextField) e.getSource() == displayF) {
s = displayF.getText().trim();
degrees = Double.parseDouble(s);
fc.setFahrenheit(degrees);
degrees = fc.getCelsius();
displayC.setText(displayFormat.format(degrees));
} else {
s = displayC.getText().trim();
degrees = Double.parseDouble(s);
fc.setCelsius(degrees);
degrees = fc.getFahrenheit();
displayF.setText(displayFormat.format(degrees));
}
}
}
And from there I'm supposed to write and test FCConverter.java I've come up with:
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.text.DecimalFormat;
public class FCConverter
{
private double Celsius;
private double Fahrenheit;
public double setFahrenheit (double degrees)
{
Celsius = (degrees - 32) * (5 / 9);
return 0;
}
public double getCelsius ()
{
return Celsius;
}
public double setCelsius (double degrees)
{
Fahrenheit = (degrees * 9 / 5 + 32);
return 0;
}
public double getFahrenheit ()
{
return Fahrenheit;
}
}
It's probably horrendous in terms of style, but I just wanted to get some working code that got past the compiler (hence the "return 0;"s which I'm fairly certain can be circumvented in a much more fashionable manner).
What I want to know is, when I test this in appletviewer or in browser form, the Celsius to Fahrenheit conversion works fine, but the Fahrenheit to Celsius conversion yields only 0.0 and -0.0. I don't understand what's wrong since the part I've designed seems fairly symmetrical. Shouldn't it be the case that both or neither conversion method works?
Upvotes: 4
Views: 5856
Reputation: 1
import java.util.Scanner;
public class HelloWorld {
public static void main(String[] args) {
Scanner reader = new Scanner(System.in); // Reading from System.in
System.out.println("Enter the number of Fahrenheit temperatures to convert to Kelvins");
// opts for the user to enter a number
int F = reader.nextInt() ; // Scans the next token of the input
double f = 5/9d;
System.out.println(f);
double x = F -32;
System.out.println(x);
double K = (f*x)+ 273.0; // the formulae to calculate temperature in Kelvin
System.out.println( +F + " Fahrenheit is equal " +K + " Kelvins" ) ;
reader.close();
}
}
Upvotes: -1
Reputation: 156
If you don't return anything set the return type to void. If you like to return doubles, you have to use doubles in calculations. 5/9 is always zero because 5 and 9 are integers. 5.0/9.0 is a different calculation on doubles.
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.text.DecimalFormat;
public class FCConverter
{
private double Celsius;
private double Fahrenheit;
public void setFahrenheit (double degrees)
{
Celsius = (degrees - 32.0) * (5.0 / 9.0);
}
public double getCelsius ()
{
return Celsius;
}
public void setCelsius (double degrees)
{
Fahrenheit = (degrees * 9.0 / 5.0 + 32.0);
}
public double getFahrenheit ()
{
return Fahrenheit;
}
}
Upvotes: 0
Reputation: 31182
change (5 / 9)
to (5.0 / 9.0)
to let java know, that you want real numbers division.
Upvotes: 0
Reputation: 11662
The problem seems to be 5/9. They are seen as an integer, and 5/9 is 0.something which is 0 as an integer. So whatever * 0 = +-0 :)
Place a "d" after the numbers, (5d/9d) forcing the compiler to consider them doubles.
Upvotes: 3
Reputation: 648
In integer math (5 / 9) = 0.
and (degrees - 32) * (5 / 9); will always be 0 you need to use doubles or something.
Upvotes: 3