CODEWITHSUNDEEP
typescriptjavascript-objectsspread-syntax
jorgen
jorgen

Reputation: 3593

Typescript does not want to spread type that's object by exclusion

I'm having issues spreading an externally imported type that's an object by way of Exclude. To demonstrate:

const f = (): object => ({});
const v = {...f()}; // valid -> OK

const f = (): object | string => ({});
const v = {...f()}; // invalid -> OK

const f = (): Exclude<object | string, "string"> => ({});
const v = {...f()}; // invalid -> PROBLEM

In the last snippet I would expect the Exclude to make the type valid. Is this me thinking about it wrongly, or is there another way of fixing this? (the type exemplified by object is an external import I can't change).

Upvotes: 0

Views: 103

Answers (1)

Matthieu Riegler
Matthieu Riegler

Reputation: 55544

You made a typo in the exclude : You want to exclude the type string not the type "string" (which is a string that can only have the value "string")

const f = (): Exclude<object | string, string> => ({});
const v = { ...f2() }; // ok

Playground

Upvotes: 1

Related Questions