CODEWITHSUNDEEP
pythonpython-3.x
Ilya
Ilya

Reputation: 1

How do I properly open an image from a folder to process it?

I need to open images and edit them. But when opened, "no such file or directory" or "<ImagingCore object at 0x0000020625552F70>" comes out. The path is specified correctly, checked several times. How do I open the image correctly? Also how can I save an already edited image to another folder with the same name? '''

    from PIL import Image
    import os
    def convertImage():
        folder_dir = "C:\проект\Images"
        for images in os.listdir(folder_dir):
        img = Image.open(images)
        img = img.convert("RGBA")

'''

Upvotes: 0

Views: 228

Answers (1)

Hidi Eric
Hidi Eric

Reputation: 364

'No such file or directory' is caused by the path. It has backslashes, which is an escape character. So the correct way to define your path is:

folder_dir = "C:\\project\\Images"

To save the edited image you can use:

img.save('path/to/output/img')

Upvotes: 1

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