CODEWITHSUNDEEP
regexgroovy
sshekhar1980
sshekhar1980

Reputation: 367

Groovy regex not matching

I have rpm packages that are named like pkg-name.0.15.0-6.x86_64.rpm. I want to extract two strings out of this:

  1. Just the name without version, release, or architecture. So in this case it would be pkg-name
  2. Then I want to extract the name with the version and release. So in this case it would be pkg-name.0.15.0-6

I tried this code below but I am not getting any match and I cannot figure out why

fullRpmName = "pkg-name.0.15.0-6.x86_64.rpm"
def matcher = (fullRpmName =~ /((.*)\\.\\d+\\.\\d+.\\d+-\\d+\\..*).x86_64\\.rpm/)
println matcher.group(1)
println matcher.group(2)

Upvotes: 0

Views: 302

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626845

You can use

String fullRpmName = "pkg-name.0.15.0-6.x86_64.rpm"
    def matcher = fullRpmName =~ /^((.*?)\..*)\.x86_64\.rpm/
    if (matcher) {
        println matcher.group(2) // pkg-name
        println matcher.group(1) // pkg-name.0.15.0-6
}

See the Groovy demo online. See the regex demo.

Details

  • ^ - start of string
  • ((.*?)\..*) - Group 1:
    • (.*?) - Group 2: any zero or more chars other than line break chars as few as possible
    • \. - a dot
    • .* - any zero or more chars other than line break chars as many as possible
  • \.x86_64\.rpm - a .x86_64.rpm string.

A bit more complex is a regex like ^(([^.]*)(?:[-.]\d+)*)\.x86_64\.rpm (see demo):

  • [^.]* - zero or more chars other than a dot
  • (?:[-.]\d+)* - zero or more repetitions of a - or . followed with one or more digits.

Upvotes: 0

Aaron Meese
Aaron Meese

Reputation: 2213

I modified your regex to match the package naming convention, you can see a working example here:

((.*)\.\d+\.\d+\.\d+-\d+)\.x86_64\.rpm

Upvotes: 1

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