CODEWITHSUNDEEP
sed
freshGrad
freshGrad

Reputation: 51

How to replace a specific character in bash

I want to replace '_v' with a whitespace and the last dot . into a dash "-". I tried using

sed 's/_v/ /' and tr '_v' ' '

Original Text

src-env-package_v1.0.1.18

output

src-en -package 1.0.1.18

Expected Output

src-env-package 1.0.1-18

Upvotes: 2

Views: 94

Answers (2)

potong
potong

Reputation: 58558

This might work for you (GNU sed):

sed -E 's/(.*)_v(.*)\./\1 \2-/' file

Use the greed of the .* regexp to find the last occurrence of _v and likewise . and substitute a space for the former and a - for the latter.

If one of the conditions may occur but not necessarily both, use:

sed -E 's/(.*)_v/\1 /;s/(.*)\./\1-/' file

Upvotes: 2

RavinderSingh13
RavinderSingh13

Reputation: 133760

With your shown samples please try following sed code. Using sed's capability to store matched regex values into temp buffer(called capturing groups) here. Also using -E option here to enable ERE(extended regular expressions) for handling regex in better way.

Here is the Online demo for used regex.

sed -E 's/^(src-env-package)_v([0-9]+\..*)\.([0-9]+)$/\1 \2-\3/' Input_file

OR if its a variable value on which you want to run sed command then use following:

var="src-env-package_v1.0.1.18"
sed -E 's/^(src-env-package)_v([0-9]+\..*)\.([0-9]+)$/\1 \2-\3/' <<<"$var"

src-env-package 1.0.1-18

Bonus solution: Adding a perl one-liner solution here, using capturing groups concept(as explained above) in perl and getting the values as per requirement.

perl -pe 's/^(src-env-package)_v((?:[0-9]+\.){1,}[0-9]+)\.([0-9]+)$/\1 \2-\3/'  Input_file

Upvotes: 1

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