CODEWITHSUNDEEP
javascriptpythonhtmldjangoajax
Fletchy
Fletchy

Reputation: 351

Ajax call run by form submission and will pass data to a separate views.py template

I am building a web application using Django. I have a search function on my index page. When a user submits the form an AJAX call should be executed. This AJAX call should take all the needed data from the form and pass it over to a completely separate views.py template that will make API GET requests using that data and build a new page using that separate template.

As of right now it is not loading the separate views.py template, I am unsure if I am passing the data correctly however I do see /searchresults?searchType=data1&executeLocation=data2 in my console because my AJAX call is returning on success currently. It is safe to assume that I have all the data needed in the data1 and data2 variables, I just need help redirecting to the new page and passing the data along with the redirect.

My code:

urls.py

 # The home page
 path('', views.index, name='home'),
 # Search results page
 path('searchresults', views.search_results, name='searchresults'),

AJAX

function getSearchResults(searchType,executeLocation,csrf_token) 
{
    $.ajax(
    {
        type: $(this).attr('method'),
        url: "searchresults", //The URL you defined in urls.py
        data : 
        {
            searchType: searchType,
            executeLocation: executeLocation,
            csrfmiddlewaretoken: csrf_token
        },
        dataType: 'text',
        success: function(response) // currently executes success (but not correct outcome)
        {
            console.log(response);
            alert('winner winner chicken dinner');
        },
        error: function(response)
        {
            console.log(response);
            alert('failure');
        }
    }).done(function(data)
    {
        console.log(data)
    });
}

index.html

<form method="POST" action="{% url 'searchresults'%}">
...
<button type="submit" onclick="getSearchResults('data1','data2','{{csrf_token}}')">Submit</button>
</form>

views.py

def search_results(request):
    context = {}
    context['requestData'] = request.POST
    html_template = loader.get_template('search/searchresults.html')
    return HttpResponseRedirect(html_template.render(context, request))

An acceptable solution should be able to do the following tasks:

  1. Redirect the user to the search_results page
  2. Pass the form data to the search_results page somehow

Upvotes: 0

Views: 34

Answers (1)

Fletchy
Fletchy

Reputation: 351

After assistance from @AminMir I was able to get a working solution. It turns out I do not need AJAX but I did need a forms.py file.

view.py

def index(request):
    context = {'segment': 'index'}
    context['SearchForm'] = SearchForm()
    return HttpResponse(html_template.render(context, request))

forms.py

from django import forms

class SearchForm(forms.Form):
    searchType = forms.CharField(max_length = 100)
    executedLocation = forms.CharField(max_length = 100)
    searchValue = forms.CharField(max_length = 100)

index.html

<form method="POST" action="{% url 'searchresults'%}">
  {% csrf_token %}
  {{ SearchForm.as_ul }}
  <input type="submit" value="submit">Search</button>
</form>

This form will then post my data to my views.py for my search_result page which is left unchanged.

Upvotes: 1

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