Reputation: 5
i want to convert u32 into ASCII bytes.
input: 1u32
output [49]
This was my try, but its empty with 0u32 and also using Vec, i would prefer ArrayVec but how do i know the size of the number. Is there any simple way to do this , without using any dynamic allocations?
let mut num = 1u32;
let base = 10u32;
let mut a: Vec<char> = Vec::new();
while num != 0 {
let chars = char::from_digit(num % base,10u32).unwrap();
a.push(chars);
num /= base;
}
let mut vec_of_u8s: Vec<u8> = a.iter().map(|c| *c as u8).collect();
vec_of_u8s.reverse();
println!("{:?}",vec_of_u8s)
Upvotes: 0
Views: 359
Reputation: 60051
Use the write!
macro and ArrayVec
with the capacity set to 10 (the maximum digits of a u32
):
use std::io::Write;
use arrayvec::ArrayVec; // 0.7.2
fn main() {
let input = 1u32;
let mut buffer = ArrayVec::<u8, 10>::new();
write!(buffer, "{}", input).unwrap();
dbg!(buffer);
}
[src/main.rs:10] buffer = [
49,
]
Upvotes: 1