Reputation: 409
I know this question has been asked before but the solutions did not work for me. I am trying to save the new ordering of items to the database.
I have simplified it very considerably but this is the basic idea of it. I have a form with a sortable list embedded in it.
<form id="itemlist">
<ul id="itemsort">
<li id="Item_1">Item<input type="hidden" name="itemid[]" value="itemsRowID01"/></li>
<li id="Item_2">Item<input type="hidden" name="itemid[]" value="itemsRowID02"/></li>
<li id="Item_3">Item<input type="hidden" name="itemid[]" value="itemsRowID03"/></li>
<li id="Item_4">Item<input type="hidden" name="itemid[]" value="itemsRowID04"/></li>
</ul>
</form>
I have JQuery and JQuery UI Loaded and the The Following code enables the sortable list function and posts the item ids and New sort order to a php script. the "editor" variable is a public variable that is set on load it works fine. The sorting works fine but the neworder value that posts doesn't seem to change when I re-order the list.
//sorting feature
$("#itemsort").live('hover', function() {
$("#itemsort").sortable({
opacity:.5,
update : function () {
var neworder = $('#itemsort').sortable('serialize');
var inputs = serializePost('#itemlist');
$.post("core/actions.php",{
'order': editor,
'inputs': inputs,
'neworder': neworder},function(){
alert("Order saved.", 1);
});
}
});
});
On actions.php...
if(isset($_POST['order'])){
//set a variable for each post
$batchid = $_POST['inputs']['itemid'];
parse_str($_POST['neworder'], $neworder);
//count the number of entries to be ordered
$count = count($batchid);
//use the count to create an incremental loop for each item to be updated.
$i=0;
while ($i <= $count) {
$query ="UPDATE {$_POST['order']} SET order=$neworder[item][$i] WHERE id=$batchid[$i]";
++$i;
}
}
I'm not sure why the order I get for each item will not change.
Any Ideas?
-L
Upvotes: 1
Views: 24382
Reputation: 409
$("#list").live('hover', function() {
$("#list").sortable({
update : function () {
var neworder = new Array();
$('#list li').each(function() {
//get the id
var id = $(this).attr("id");
//create an object
var obj = {};
//insert the id into the object
obj[] = id;
//push the object into the array
neworder.push(obj);
});
$.post("pagewhereyouuselist.php",{'neworder': neworder},function(data){});
}
});
});
Then in your PHP file, or in this example "pagewhereyouuselist.php"
$neworderarray = $_POST['neworder'];
//loop through the list of ids and update your db
foreach($neworderarray as $order=>$id){
//you prob jave a connection already i just added this as an example
$con = mysql_connect("host","username","password");
if (!$con){
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_db", $con);
mysql_query("UPDATE table SET order = {$order} WHERE id = {$id}");
mysql_close($con);
}
that should do it i didn't test it as it is an example connection. the actual script I am actually using is more specific to my program this is a simplified version to show the concept
Upvotes: 11
Reputation: 3487
Try this:
Your HTML fields
<form id="itemlist" method="POST">
<ul id="itemsort">
<li id="Item_1">Item 1<input type="hidden" name="itemid[]" value="itemsRowID01"/></li>
<li id="Item_2">Item 2<input type="hidden" name="itemid[]" value="itemsRowID02"/></li>
<li id="Item_3">Item 3<input type="hidden" name="itemid[]" value="itemsRowID03"/></li>
<li id="Item_4">Item 4<input type="hidden" name="itemid[]" value="itemsRowID04"/></li>
</ul>
</form>
JS to send order:
$("#itemsort").live( 'hover', function() {
$("#itemsort").sortable({
update: function () {
var inputs = $('#itemlist').serialize();
$.post("./jq-ui-test.php", inputs, alert("Order saved.") );
}
});
});
Saving order:
if( isset( $_POST['itemid'] ) && is_array( $_POST['itemid'] ) ) {
foreach( $_POST['itemid'] as $order => $item ) {
$order = intval( $order );
$item_esc = mysql_real_escape_string( $item );
$sql_query = "UPDATE {$_POST['order']} SET order={$order} WHERE id = '{$item_esc}'";
}
}
Also, if you want that start order start from 1 ( not from 0 ) change $order = intval( $order );
to $order = intval( $order ) + 1;
Upvotes: 7