CODEWITHSUNDEEP
python
locoboy
locoboy

Reputation: 38920

How to reformat a string in python?

Right now I have a string in the form [email protected]@zzz.com and I want to strip off the @zzz.com so that it comes out as [email protected].

Upvotes: 2

Views: 272

Answers (7)

Musaab
Musaab

Reputation: 1604

Not sure if this code is too much for the task, but here ya go.

data = "[email protected]@zzz.com"

def cleaner(email):
   counter = 0
   result = ''
   for i in data:
      if i == "@":
        counter += 1
      if counter == 2:
        break
      result += i
   return result

data = cleaner(data)

data = '[email protected]'

Just pass the data to the cleaner function. For example: cleaner(data) will return the correct answer.

edit: what gribbler posted is 1000x better than this...lol I am still learning :)

data.rpartition('@')[0]

Upvotes: 0

John La Rooy
John La Rooy

Reputation: 304147

>>> '[email protected]@zzz.com'.rpartition('@')[0]
'[email protected]'

Upvotes: 3

Plaban Nayak
Plaban Nayak

Reputation: 176

string = "[email protected]@zzz.com"

print string[0:string.rfind('@')]

can help you

Upvotes: 0

Matthew Schinckel
Matthew Schinckel

Reputation: 35619

You can use:

"[email protected]@zzz.com".replace("@zzz.com", "")

If you know it will always be "@zzz.com".

Otherwise, you could try:

data = "[email protected]@zzz.com"
if data.count("@") == 2:
    data = data.rsplit('@', 1)[0]

Or, more generally:

data = "[email protected]@zzz.com@___.com"
if data.count("@") > 1:
    data = data.rsplit('@', data.count("@")-1)[0]

You can learn more about the string methods I have used at Python : String Methods

Upvotes: 3

kumar_m_kiran
kumar_m_kiran

Reputation: 4022

This would work. Please check it. 

st='[email protected]@zzz.com'  
print st  
newstr=st[0:st.rfind('@')]  
print newstr

Idea is to use rfind and strip find the @ symbol from the end.

Upvotes: 0

TeamBlast
TeamBlast

Reputation: 428

string = "[email protected]@zzz.com"
string = "@".join(string.split("@")[:2])

Simple way to do the job. I don't think it's very safe though.

Upvotes: 1

phs
phs

Reputation: 11051

$ python
Python 2.6.6 (r266:84292, Nov 19 2010, 21:55:12) 
[GCC 4.2.1 (Apple Inc. build 5664)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import re
>>> re.sub('@[^@.]*\.com$', '', '[email protected]@zzz.com')
'[email protected]'

Upvotes: 0

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