Reputation: 115
Here is my code
function first() {
console.log("first")
return function second() { return console.log("second") }
}
let foo = first() // It is outputing "first" once
foo() // Output is "second"
first()() // Output is "first" "second"
What I do not understand is why foo()
is giving a different output comparing to first()()
. If foo
= first()
, then I think it should have the same output.
The second question (and less important) is: how can I avoid the output when assigning the variable let foo = first()
?
Upvotes: 0
Views: 42
Reputation: 4147
It's because you are not assigning first
to foo
when you do first()
, you are calling first
. When first
is called, it logs "first"
to the console and then it returns the function second
. So foo
gets assigned the return value of first
which is the function second
.
Assigning first to foo
You can assign the function first
to foo
via normal assignment without calling it:
let foo = first; // now foo === first
Assigning the returned function second
to foo
let foo = first(); // note the use of (); now foo === second
Immediately calling the returned function
In the last line, you are doing two things in one line. The first first()
(no pun intended) returns the second
function (and thereby executes the console.log
statement) which is immediately called via ()
(and executes the other console.log
statement). That's why you see it logging "first"
and "second"
.
let foo = first()(); // note the doubled use of (); now, foo === undefined
Whatever are we doing here?
Although it might seem a bit strange at first, the technique of passing and/or returning a function to/from another function is very useful - so much that it has a name: Higher Order Function (or - as I like to call it - HOF).
One pretty common example of a HOF is Array.prototype.map
. When you pass a function to .map
, it projects the function onto every element in the array and collects the resulting value of each projection into a new array which it finally returns.
A concrete example of a HOF besides .map
: Suppose you have to call .split
on different input strings that come from different sources but you always want to split the strings on the same character. Create a makeSplitter
HOF:
function makeSplitter(splitOn) { // <-- HOF
return function (inputString) { // <-- return value of HOF
return inputString.split(splitOn);
}
}
With this, you can create a general function that splits an input string, say, by slash:
const splitSlashes = makeSplitter(/\//g);
You can think of splitSlashes
as if it had been written like so:
const splitSlashes = function (inputString) {
return inputString.split(/\//g);
}
And now you can use that to split various strings that contain slashes into separate parts:
console.log(splitSlashes('08/12/2022')); // logs ['08', '12', '2022']
console.log(splitSlashes('www.example.com/path/to/x/')); // logs ['www.example.com', 'path', 'to', 'x']
If you need another function that - for example - splits a string on .
, just use makeSplitter
with another argument:
const splitDots = makeSplitter(/\./g);
Upvotes: 2
Reputation: 1154
Output of a function is a value in return statement but not console.log in a function body
function first() {
return function second() { return 'second' }
}
let foo = first() //now a function is in foo variable
foo() // "second"
first()() // "second"
the same output in both cases
Upvotes: 1