CODEWITHSUNDEEP
pythonmypypython-typing
zyxue
zyxue

Reputation: 8840

how to type a function that returns None if input is string otherwise return the input as is

I wonder what's the right way to type annotate a python function as below?

def f(value):
    if isinstance(value, str):
        return None
    return value

This is a toy example that is analogous to a python I encountered that needs type annotated. Using Union like

def f(value: Union[float, int, str]) -> Union[float, int, None]:
    if isinstance(value, str):
        return None
    return value

doesn't feel right because it doesn't enforce the rules

Let's assume the input can only be one of int/float/str.

Upvotes: 1

Views: 807

Answers (1)

Samwise
Samwise

Reputation: 71454

You can use typing.overload to narrow the types of return values based on the types of the arguments:

from typing import overload

@overload
def f(value: str) -> None: ...

@overload
def f(value: int) -> int: ...

@overload
def f(value: float) -> float: ...

def f(value: int|float|str) -> int|float|None:
    if isinstance(value, str):
        return None
    return value

Note that the actual implementation uses a union of all the possible argument and return types.

If a call to the function conforms to one of the overload stubs, the appropriate return type is inferred:

reveal_type(f("foo"))  # revealed type is "None"
reveal_type(f(123))    # revealed type is "builtins.int"

Upvotes: 2

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