Reputation: 53
How to use a string containing a class name to reference a class itself?
See this (not working) exemple...
class WrapperClass:
def display_var(self):
#FIXME: self.__class_name__.__name__ is a string
print self.__class__.__name__.the_var
class SomeSubClass(WrapperClass):
var = "abc"
class AnotherSubClass(WrapperClass):
var = "def"
And an obvious error message:
>>> b = SomeSubClass() >>> b.display_var() Traceback (most recent call last): File "", line 1, in File "", line 4, in display_var AttributeError: 'str' object has no attribute 'the_var' >>>
Thanks!
Upvotes: 4
Views: 11826
Reputation: 309
There exists a case where one has the name of a class, but not a reference to it. A tkinter Entry widget has a validate method which returns to the callback function (%W parameter) the name of the widget, not a reference to it. If you have a window with an array of entry fields, It is inconvenient to use a different callback function for each entry. Converting the string name to the reference in the callback function is a more efficient way to associate the callback to the source of the validate event. I would have commented on Devin's answer, but don't have the reputation points to make comments yet.
Upvotes: 0
Reputation: 536725
How to use a string containing a class name to reference a class itself?
Classes aren't special, they're just values contained in variables. If you've said:
class X(object): pass
in global scope, then the variable ‘X’ will be a reference to the class object.
You can get the current script/module's global variables as a dictionary using ‘globals()’, so:
classobj= globals()[self.__class__.__name__]
print classobj.var
(locals()
is also available for local variables; between them you shouldn't ever need to use the awful eval()
to access variables.)
However as David notes, self.__class__
is already the classobj
, so there's no need to go running about fetching it from the global variables by name; self.__class__.var
is fine. Although really:
print self.var
would be the usual simple way to do it. Class members are available as members of their instances, as long as the instance doesn't overwrite the name with something else.
Upvotes: 9
Reputation: 95616
Depending on where you get this string, any general method may be insecure (one such method is to simply use eval(string)
. The best method is to define a dict mapping names to classes:
class WrapperClass:
def display_var(self):
#FIXME: self.__class_name__.__name__ is a string
print d[self.__class__.__name__].the_var
class SomeSubClass(WrapperClass):
the_var = "abc"
class AnotherSubClass(WrapperClass):
the_var = "def"
d = {'WrapperClass': WrapperClass, 'SomeSubClass': SomeSubClass, 'AnotherSubClass': AnotherSubClass}
AnotherSubClass().display_var()
# prints 'def'
Upvotes: 3
Reputation: 12823
Your example would work if you called print self.__class__.var
. I don't think there's any need to use the name.
Upvotes: 2