CODEWITHSUNDEEP
neo4jcypher
drdot
drdot

Reputation: 3347

neo4j turn paths into subgraph

Say I have the following graph

       Z
  /         \ 
 /           \  
A -> B -> C -> D
 \          /
  -> X -> Y

I compute the paths

match p=((:A)-[*]->[:D])
return p

This will return three paths (rows): AZD, ABCD and AXYD

But I would like to return a subgraph that contains all the paths between A and D. so the result should be a subgraph. My understanding is that the only format for a subgraph return is nodes and relationships. So a query like below

// query logic
return nodes, relationships

What should I write in the query logic? NOTE:

  1. this is not the entire graph, there are other subgraphs in my graph, so returning the entire graph does not work
  2. A and D are just node types here, there will be many type A and type D nodes and there will be one or multiple paths between each A and D node pair.

Upvotes: 0

Views: 57

Answers (1)

Graphileon
Graphileon

Reputation: 5385

One way to retrieve the unique set of nodes and relationships is using apoc

MATCH p=((:A)-[*]->(:D))    
RETURN apoc.coll.toSet(
            apoc.coll.flatten(
                 COLLECT(nodes(p))
            )
       ) AS nodes,
       apoc.coll.toSet(
            apoc.coll.flatten(
                 COLLECT(relationships(p))
            )
       ) AS relationships

Upvotes: 1

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