CODEWITHSUNDEEP
pythonfunctiontkinterbuttonswitch-statement
ddoch003
ddoch003

Reputation: 23

Tkinter button acts only as a one-time switch instead of switching multiple times

this is the first question I am posting here. I recently created a window in Tkinter that contains a frame. After clicking a button a label containing text should appear inside the frame. When clicking the button again - the label should disappear. It works fine until I click the button for a third time to call the label inside the frame again.

Here is the code:

from tkinter import *

root=Tk()

root.geometry("500x500+100+100")
root.title("Switch label")
root.resizable(False,False)

is_off=True

def label_disappear():
    global label
    global is_off

    label.destroy()
    button.config(text="Add",command=label_appear)
    is_off=True

def label_appear():
    global label
    global is_off

    if is_off:
        label.place(x=20,y=20)
        button.config(text="Remove",command=label_disappear)
        is_off=False
    else:
        label_disappear()


frame=Frame(root,bg="light green",width=460,height=200)
frame.place(x=20,y=20)


label=Label(frame,text="This is label",bg="light green")

button=Button(root,text="Add",command=label_appear)
button.place(relx=0.5,y=250,anchor="center")

root.mainloop()

and here is the error that PyCharm throws:

Image of the error

How can I change it so that it works as a real switch and not only as one time on/off button?

Thank you in advance!

Upvotes: 0

Views: 428

Answers (1)

acw1668
acw1668

Reputation: 46669

It is because you have destroyed the label inside label_disappear(). If you want the label to be shown again, replace label.destroy() by label.place_forget() inside label_disappear():

def label_disappear():
    global label
    global is_off

    label.place_forget()  # don't destroy the label, just make it invisible
    button.config(text="Add",command=label_appear)
    is_off=True

Upvotes: 1

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