CODEWITHSUNDEEP
javaregexstring
Anna Stasinopoulou
Anna Stasinopoulou

Reputation: 23

Regex- Allow * in the beginning and in the end of a string and allow only *

I need to write a regex that validates the input for a city. Except for characters only spaces are allowed and * acts as a wildcard character, so it can be either in the end or in the beginning of the string. * character should be allowed to be the only input as well.

Accepted strings:

Not accepted strings:

I have written this, but it doesn't allow only '*" as input. Any ideas? '^.*[A-Za-zÀ-ÖØ-öø-ž ]{1,34}.*$'

Upvotes: 2

Views: 206

Answers (3)

Zak
Zak

Reputation: 1110

Escape the asterisk with a backslash so that it isn't interpreted as a greedy repetition quantifier: \*.

Use beginning (^) and end ($) anchors to ensure that your asterisk can only occur at the start or end of the string.

Lastly, use a negative lookahead ((?!...)) to ensure that the match can't only be two asterisks.

Putting it all together, you get:

(?!^\*\*$)^\*?[\p{L} ]*\*?$

Upvotes: 1

anubhava
anubhava

Reputation: 785316

Here is a regex that might be shorter and efficient:

^(?:\*?[\p{L}\h]+\*?|\*)$

RegEx Demo

RegEx Breakup:

  • ^: Start
  • (?:: Start non-capture group
    • \*?: Match an optional *
    • [\p{L}\h]+: Match 1+ of any unicode letter or horizontal whitespace
    • \*?: Match an optional *
    • |: OR
    • \*: Match a single *
  • ): End non-capture group
  • $: End

Java Code:

final String regex = "^(?:\\*?[\\p{L}\\h]+\\*?|\\*)$";
String s = "* cit *";
System.out.println( s.matches(regex) );

Upvotes: 1

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626950

You can use

^(?:\*|\*?\p{L}+(?:\h+\p{L}*)*+\*?)$

See the regex demo.

Details:

  • ^ - start of string
  • (?:\*|\*?\p{L}+(?:\h+\p{L}*)*+\*?) - either of the two patterns:
    • \* - an asterisk
    • | - or
    • \*? - an optional asterisk
    • \p{L}+ - one or more letters
    • (?:\h+\p{L}*)*+ - one or more repetitions of one or more horizontal whitespaces followed with zero or more letters
    • \*? - an optional asterisk
  • $ - end of string.

In Java:

bool matched = text.matches("\\*|\\*?\\p{L}+(?:\\h+\\p{L}*)*+\\*?");

Upvotes: 3

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