CODEWITHSUNDEEP
pythonregex
YIF99
YIF99

Reputation: 61

using regex to select value in python

I want regex to select 00:01:00, however, it takes 07:59:00. So decided to search not only based on date format, but to look for " in front of date format as well.

lineItems = ["2022-08-15T07:59:00,row1,"00:01:00","2022-08-15T08:00:00"]

lineItems is a list. I have to pick the format that is similar to 00:01:00

The script I use is below:

matches = re.search('(\d{2}):(\d{2}):(\d{2})', str(lineItems))

Could you please assist to edit the script, so it looks for " in front of datetime, but grab only DateTime without ".

Thanks

Upvotes: 0

Views: 79

Answers (2)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626794

You can use

import re
 
lineItems = ["2022-08-15T07:59:00","row1","00:01:00","2022-08-15T08:00:00"]
r = re.compile(r'\d{2}:\d{2}:\d{2}')
print( list(filter(r.fullmatch, lineItems)) )
# => ['00:01:00']

See the Python demo.

Note that r.fullmatch requires a full string match, so there is no need adding anchors to the pattern.

Upvotes: 2

VvdL
VvdL

Reputation: 3210

You could use a positive lookbehind to make sure it's preceded by ".

matches = re.search('(?<=")(\d{2}):(\d{2}):(\d{2})', str(lineItems))

Upvotes: 0

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