CODEWITHSUNDEEP
pythontry-catch
ilra
ilra

Reputation: 145

Try except not catching FileNotFoundError

I'm trying to catch the FileNotFoundError and break the code when it occurs, but for some reason it's not working, im still getting the error and the code is not breaking, here is my code

file_name = input("Choose a file: ")
def split_columns(file_name):
    x_values = []
    y_values = []     
    try:                                            
        with open(file_name) as f:
            for line in f:
                row_values = line.split()
                print(row_values)
                x_values.append(float(row_values[0]))
                y_values.append(float(row_values[1]))
    except FileNotFoundError:
        print('This file does not exist, try again!')
        raise
    return x_values, y_values

What did i do wrong?

Upvotes: 1

Views: 709

Answers (1)

Barmar
Barmar

Reputation: 780798

Take the try/except out of the function, and put it in the loop that calls the function.

def split_columns(file_name):
    x_values = []
    y_values = []     
    with open(file_name) as f:
        for line in f:
            row_values = line.split()
            print(row_values)
            x_values.append(float(row_values[0]))
            y_values.append(float(row_values[1]))
    return x_values, y_values

while True:
    file_name = input("Choose a file: ")
    try:
        x_values, y_values = split_columns(file_name)
        break
    except FileNotFoundError:
        print('This file does not exist, try again!')

Upvotes: 1

Related Questions