CODEWITHSUNDEEP
python
muhammad ingar
muhammad ingar

Reputation: 13

Why does my code repeat instead carry on when i input an integer?

it keeps repeating please help me

new_custom = ""
while new_custom !=["y","n"]:
    new_custom = input("are you a new customer y/n \n").lower
    if new_custom == "y":
        if miles <= 5:
            print (7)
        else:
            print( 7 + ((miles - 5) * 2))
    elif new_custom == "n":
        if miles <= 5:
            print(8)
        else:
              print(8+((miles-5)*2))

i cant figure out why it keeps repeating

Upvotes: 0

Views: 40

Answers (3)

David
David

Reputation: 321

There are 2 errors present in your code:

new_custom !=["y","n"]

This does not check if a string is contained in the list; it checks to see if a list containing the same elements is present.

input("are you a new customer y/n \n").lower

By missing the brackets your script does not realise that lower is a function.

Using these 2 lines will correct your code:

while new_custom not in ["y","n"]:
    new_custom = input("are you a new customer y/n \n").lower()

Upvotes: 1

SuperKingCheese
SuperKingCheese

Reputation: 22

You missed the parentheses on your lower case check. Should be .lower() and the code should continue but the next error will be miles is not defined.

Upvotes: 0

Daniel Ben-Shabtay
Daniel Ben-Shabtay

Reputation: 350

your while condition should be like this:

miles = 8
new_custom = ""
while new_custom not in ["y","n"]:
    new_custom = input("are you a new customer y/n \n").lower()
    if new_custom == "y":
        if miles <= 5:
            print (7)
        else:
            print( 7 + ((miles - 5) * 2))
    elif new_custom == "n":
        if miles <= 5:
            print(8)
        else:
              print(8+((miles-5)*2))

Upvotes: 0

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