CODEWITHSUNDEEP
pysparkapache-spark-sql
Rory
Rory

Reputation: 383

Create dictionary in pyspark dataframe

I have dataframe:

df = spark.createDataFrame(
    [
        (2022,'A1', "cat", 'eng', 3, 56.768639), 
         (2022,'A1', "rabbit", 'eng', 10, 56.768639), 
         (2022, 'A2', "dog", 'eng', 10, 54.114841),
           (2022, 'A2', "mouse", 'eng', 20, 81.114841),
    ],
    ["data",'group', "word", 'lang', 'count', 'value']  # add your column names here
)
df.show()
+----+-----+------+----+-----+---------+
|data|group|  word|lang|count|    value|
+----+-----+------+----+-----+---------+
|2022|   A1|   cat| eng|    3|56.768639|
|2022|   A1|rabbit| eng|   10|56.768639|
|2022|   A2|   dog| eng|   10|54.114841|
|2022|   A2| mouse| eng|   20|81.114841|
+----+-----+------+----+-----+---------+

I want to create a lst column in which an array of dictionaries:

+----+-----+----+--------------------------------------------------------------------------------------------------+
|data|group|lang|lst                                                                                               |
+----+-----+----+--------------------------------------------------------------------------------------------------+
|2022|A1   |eng |[{count : 3, value : 56.768639, word : cat}, {count : 10, value : 56.768639, word :rabbit}]|
|2022|A2   |eng |[{count : 10, value : 54.114841, word : dog}, {count : 20, value : 81.114841, word : mouse}]|

I tried this:

map_values = df\
    .groupBy('data', 'group', 'lang')\
    .agg(F.collect_list(F.create_map(F.col('word'), F.col('count'), F.col('value'))).alias('descr'))

But it gives me an error

cannot resolve 'map(`word`, `count`, `value`)' due to data type mismatch: map expects a positive even number of arguments.;

Upvotes: 0

Views: 313

Answers (1)

过过招
过过招

Reputation: 4244

You can first use to_json function to generate json string, then use collect_list function to aggregate.

map_values = df\
    .groupBy('data', 'group', 'lang')\
    .agg(F.collect_list(F.to_json(F.struct(F.col('count'), F.col('value'), F.col('word')))).alias('descr'))

Upvotes: 1

Related Questions