Reputation: 115
I am trying to execute local binary pattern in MATLAB using the image processing toolbox. When i execute I can't get a LBP image and LBP histogram.
clear all;
close all;
clc;
I=imread('test.png');
figure,imshow(I)
%% Crop
I2 = imcrop(I);
figure, imshow(I2)
w=size(I2,1);
h=size(I2,2);
%% LBP
scale = 2.^[7 6 5; 0 -inf 4; 1 2 3];
for i=2:w-1
for j=2:h-1
J0=I2(i,j);
I3(i-1,j-1)=I2(i-1,j-1)>J0;
I3(i-1,j)=I2(i-1,j)>J0;
I3(i-1,j+1)=I2(i-1,j+1)>J0;
I3(i,j+1)=I2(i,j+1)>J0;
I3(i+1,j+1)=I2(i+1,j+1)>J0;
I3(i+1,j)=I2(i+1,j)>J0;
I3(i+1,j-1)=I2(i+1,j-1)>J0;
I3(i,j-1)=I2(i,j-1)>J0;
LBP(i,j)=I3(i-1,j-1)*2^7+I3(i-1,j)*2^6+I3(i-1,j+1)*2^5+I3(i,j+1)*2^4+I3(i+1,j+1)*2^3+I3(i+1,j)*2^2+I3(i+1,j-1)*2^1+I3(i,j-1)*2^0;
end
end
figure,imshow(LBP)
figure,imhist(LBP)
what is the issue.i am supposed to get numbers from 0 to 255.
Upvotes: 3
Views: 5846
Reputation: 1
use : figure,imshow(uint8(LBP));
Its becuase LBP image is in DOUBLE, you need to cast it.
Upvotes: 0
Reputation: 74940
I3(i-1,j-1)=I2(i-1,j-1)>J0;
creates a logical as output. If you don't go and cast this to something else, you're image will only be zeros and ones.
The easiest way is to initialize I3
outside the loop, i.e. have I3=I2;
before you start looping. This way, all your assignments inside the loop get converted to whatever class I2
was.
Upvotes: 2