Reputation: 8037
Given this code:
dgIPs.DataSource =
from act in Master.dc.Activities
where act.Session.UID == Master.u.ID
select new
{
Address = act.Session.IP.Address,
Domain = act.Session.IP.Domain,
FirstAccess = act.Session.IP.FirstAccess,
LastAccess = act.Session.IP.LastAccess,
IsSpider = act.Session.IP.isSpider,
NumberProblems = act.Session.IP.NumProblems,
NumberSessions = act.Session.IP.Sessions.Count()
};
How do I pull the Distinct() based on distinct Address only? That is, if I simply add Distinct(), it evaluates the whole row as being distinct and thusly fails to find any duplicates. I want to return exactly one row for each act.Session.IP object.
I've already found this answer, but it seems to be a different situation. Also, Distinct() works fine if I just select act.Session.IP, but it has a column I wish to avoid retrieving and I'd rather not have to do this by manually binding my datagrid columns.
Upvotes: 1
Views: 4871
Reputation: 36037
dgIPs.DataSource =
from act in Master.dc.Activities
where act.Session.UID == Master.u.ID
group act by act.Session.IP.Address into g
let ip = g.First().Session.IP
select new
{
Address = ip.Address,
Domain = ip.Domain,
FirstAccess = ip.FirstAccess,
LastAccess = ip.LastAccess,
IsSpider = ip.isSpider,
NumberProblems = ip.NumProblems,
NumberSessions = ip.Sessions.Count()
};
Or:
dgIPs.DataSource =
from act in Master.dc.Activities
where act.Session.UID == Master.u.ID
group act.Session.IP by act.Session.IP.Address into g
let ip = g.First()
select new
{
Address = ip.Address,
Domain = ip.Domain,
FirstAccess = ip.FirstAccess,
LastAccess = ip.LastAccess,
IsSpider = ip.isSpider,
NumberProblems = ip.NumProblems,
NumberSessions = ip.Sessions.Count()
};
Upvotes: 3
Reputation: 161783
One of the overloads of Enumerable.Distinct accepts an IEqualityComparer instance. Simply write a class that implements IEqualityComparer and which only compares the two Address properties.
Unfortunately, you'll have to give a name to the anonymous class you're using.
Upvotes: 0