Reputation: 21
I have trained and tested a neural network in which I have 2 variables as my dependent variables hence, in output, there are two NumPy arrays of train and test, with each NumPy array having 2 outputs.
import pandas as pd
import numpy as np
y_test =
array([[242.14, 61.],
[179.48, 140.54],
[ 98.16, 36.05],
...,
[187.73, 111.39],
[ 52.15, 25.82],
[119.92, 54.52]])
y_pred =
array([[[178.8299 ],
[ 73.47848 ]],
[[216.90152 ],
[116.74648 ]],
[[215.67923 ],
[ 47.019424]],
...,
[[236.51259 ],
[167.34752 ]],
[[156.02226 ],
[ 61.292656]],
[[151.5344 ],
[ 56.285583]]],
and I am trying to calculate R-Square value using the following code
from sklearn.metrics import r2_score
r2 = r2_score(y_test, y_pred)
r2 = round(r2,2)
print('R2 =',r2)
However, am getting the error of ValueError: Found array with dim 3. Estimator expected <= 2.
Upvotes: 0
Views: 36
Reputation: 181
Your y_pred
array has 3 dimensions by the looks of it.
Try removing a square bracket from the start and end...
y_pred =
array([[178.8299 ],
[ 73.47848 ]],
[[216.90152 ],
[116.74648 ]],
[[215.67923 ],
[ 47.019424]],
...,
[[236.51259 ],
[167.34752 ]],
[[156.02226 ],
[ 61.292656]],
[[151.5344 ],
[ 56.285583]],
Upvotes: 0