CODEWITHSUNDEEP
pythonregex
aName
aName

Reputation: 3043

how to exclude a character once

I'm trying to exclude a character once (and everything after):
here is some example

the pattern is: (any character except =) = (any character) ,here is the result that I wanted :

I tried : ([^=]+)=([^=]+) and ([^=]+)=(.*) but it doesn't work

Upvotes: 1

Views: 50

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626689

You can use

([^,=]+)=(.*?)(?=,[^,=]+=|$)

See the regex demo.

Details:

  • ([^,=]+) - Group 1: one or more chars other than comma and =
  • = - = char
  • (.*?) - Group 2: any zero or more chars other than line break chars as few as possible
  • (?=,[^,=]+=|$) - a location that is either immediately followed with a comma and then zero or more chars other than , and = and then a = char, or end of string.

If you need to get rid of leading/trailing whitespaces, you may use this more complex pattern:

([^\s,=](?:[^,=]*[^,=\s])?)\s*=\s*(\S.*?)?\s*(?=,[^,=]+=|$)

See this regex demo.

See the Python demo:

import re
text = "val=aabbcc,val2==aabb,val3=aa==bb, val4=a=bccc"
result = re.findall(r'([^\s,=](?:[^,=]*[^,=\s])?)\s*=\s*(\S.*?)?\s*(?=,[^,=]+=|$)', text)
print(dict(result))

Output:

{'val': 'aabbcc', 'val2': '=aabb', 'val3': 'aa==bb', 'val4': 'a=bccc'}

Upvotes: 1

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