CODEWITHSUNDEEP
python
Екатерина Городкова
Екатерина Городкова

Reputation: 21

how to stop iterating after the condition is done

I have

print(list_games)
array([[77, 63],
       [94, 49],
        [58, 98],
       ...,
       [ 7,  0],
       [68, 22],
       [ 1, 32]], dtype=int64)

I need to print the first pair and their index, which satisfy the condition, but my code print all pairs. How can I fix it?

for i in range(len(list_games)):
    for j in range(len(list_games)):
        if list_games[i][0] + list_games[j][1] == 131:
            print(list_games[i][0], list_games[j][1])
            break

And I get:

77 54
94 37
58 73
51 80
80 51
74 57
66 65
61 70
87 44
40 91

Upvotes: 0

Views: 46

Answers (2)

BehRouz
BehRouz

Reputation: 1364

You can use a boolean to control if the first loop also should break or not.

loop = True
for i in range(len(list_games)):
    for j in range(len(list_games)):
        if list_games[i][0] + list_games[j][1] == 131:
            print(list_games[i][0], list_games[j][1])
            loop = False
            break
    if loop == False:
        break

Upvotes: 1

Rahul K P
Rahul K P

Reputation: 16081

The best option is to do it inside a function and return when the condition satisfies,

def match():
    for i in range(len(list_games)):
        for j in range(len(list_games)):
            if list_games[i][0] + list_games[j][1] == 131:
                return (list_games[i][0], list_games[j][1])

value = match()
print(value)

Execution:

In [1]: list_games = np.array([[77, 63], [94, 49], [58, 98],[ 7, 0], [68, 22], [ 1, 32]], dtype=np.int64)

In [2]: value = match()
   ...: print(value)
(68, 63)

Upvotes: 0

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