CODEWITHSUNDEEP
javascript
tsukingo
tsukingo

Reputation: 199

javascript variable not changed

I'm trying to do a little program to reverse a string and I'm using this approch:

var reverse = (str) => {
    let returned = [...str];
    for(let i = 0; i < returned.length; i++)
    {
        let symetrical = returned.length - i - 1;
        let temp = returned[i];
        returned[i] = returned[symetrical];
        returned[symetrical] = temp;
    }
    
    return returned.join("");
}

but when i test the function like reverse('123') I got the same input as result?

why the returned variable didn't change?

Upvotes: 0

Views: 43

Answers (1)

symlink
symlink

Reputation: 12209

You can simplify the function by creating two arrays, the array of the letters of the param str, and the results array which takes the length - 1 - i algorithm you had:

let reverse = (str) => {
    const arr1 = [...str];
    const arr2 = []
    for(let i = 0; i < arr1.length; i++)
    {
        arr2[i] = arr1[arr1.length - 1 - i];
    }
    
    return arr2.join("");
}

console.log(reverse("abcde"));

Upvotes: 1

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