CODEWITHSUNDEEP
pythonstringfunctionif-statement
Tevin
Tevin

Reputation: 1

Function output with if-else statement

Hello I have been study python for the pass few months and can't seem to figure out how to get the code below to work. The could runs but I am not receiving the output I was expected. I know strings are immutable, at first I kept using list function a realized that was incorrect but im stuck at thE moment. Not sure if I need to use a for loop to iterate through the string?

def function(input_string):
    output_string = ''
    if len(input_string)> 6:
       return input_string[1:] #Should return the string starting at index 1
    elif input_string.count('e') > 2:
       return input_string.count('e') #should return the count of 'E'
    elif input_string.isdigit():
       return input_string % 2  
#Should if string is a digit halve it example input_string = '4224' should be output_string'2114'
    else:
       return input_string[-1:0] #Should reverse the string outoutput_string='Ecetem'
            
    return output_string    

input_string = 'metecE'
output_string = function(input_string)
print(output_string)

I've tried using a for loop. This is a practice question for a test. The criteria after the # are required and it has to be in a function. I will not be allowed to change any of the code beside the logic I have with if-else statement. Any help with be greatly appreciate. I really want to figure out what I did incorrectly.

Upvotes: 0

Views: 58

Answers (1)

Omer Dagry
Omer Dagry

Reputation: 567

you had 3 mistakes:

  1. you didn't convert the input_string to int when trying to divide it

  2. you didn't use the right sign for division (/ and not %)

  3. you tried to reverse the input_string using [-1:0] when you need to do [::-1]

def function(input_string):
    if len(input_string) > 6:
        return input_string[1:]
    elif input_string.count('e') > 2:
        return input_string.count('e')
    elif input_string.isdigit():
        # you need to turn input_string to int and then use `/` to divide and not `%` 
        # (if the result to be int use `//`)
        return int(input_string) / 2
    else:
        # use [::-1] to reverse a string and not [-1:0]
        return input_string[::-1]


input_string = '4224'
output_string = function(input_string)
print(output_string)

Upvotes: 1

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