Reputation:
I'm trying to obtain the most common asnwers so we have Yes/No questions and it has i eleven questions from this one I would like to know from Yes/No which was has most answers as an example:
If in more than the half of the eleven i's has No>Yes the most common answers will be 'NO' but I'm not really sure what function I need to do this, comparing the rows 0 and 1 to know which one had more answers.
I would like to do this kind of script:
if row[0] > row1: print("No is the most common answer")
This is the example data that I have:
index i1 i2 i3 i4 i5 i6 i7 i8 i9 i10 i11
0 No 94 123 96 108 122 106.0 95.0 124 104 118 73
1 Yes 34 4 33 21 5 25.0 34.0 5 21 9 55
EDIT: Wanted result for using just the first column.
Upvotes: 2
Views: 65
Reputation: 163
To obtain a list of 'yes' and 'no' you can do:
no_count = df.iloc[0].values[1:]
yes_count = df.iloc[1].values[1:]
most_common = ['no' if no_count[i]>yes_count[i] else 'yes' for i in range(len(no_count))]
Then you can count the number of each
number_no = most_common.count("no")
number_yes = most_common.count("yes")
Upvotes: 1