CODEWITHSUNDEEP
javascript
user12475368
user12475368

Reputation:

Check if array has multiple ids

How do I solve this while using include()?

const allowedIds = [1, 3]

const allBoats = [{
  id: 1,
  name: 'titanic'
}, {
  id: 2,
  name: 'anna'
}, {
  id: 3,
  name: 'boaty McBoatface'
}, ]

const expectedResult = ['boaty McBoatface', 'titanic']

Upvotes: 1

Views: 119

Answers (5)

Abhishek
Abhishek

Reputation: 1120

if you want only those with id 1 or 3:

const selections = allBoats.filter((val)=>{return val.id === 1 || val.id ===3});
const result = selections.map((val,key)=>{ val.name}).sort()
console.log(result) //gives ["boaty McBoatface", "titanic"]

Upvotes: 0

Sash Sinha
Sash Sinha

Reputation: 22350

Consider making allowedIds a Set and then using has, which is O(1), rather than includes on an Array, which is O(N):

const allowedIds = new Set([1, 3]);
const allBoats = [
  {
    id: 1,
    name: "titanic",
  },
  {
    id: 2,
    name: "anna",
  },
  {
    id: 3,
    name: "boaty McBoatface",
  },
];
const allowedBoats = allBoats.filter(b => allowedIds.has(b.id))
                             .map(b => b.name)
                             .sort();
console.log(allowedBoats);

Other potentially useful documentation links:

Upvotes: 3

Layhout
Layhout

Reputation: 1580

const allowedIds = [1, 3]

const allBoats = [
    {
        id: 1,
        name: 'titanic'
    },
    {
        id: 2,
        name: 'anna'
    },
    {
        id: 3,
        name: 'boaty McBoatface'
    }
]

const expectedResult = allBoats.reduce((p, c) => allowedIds.includes(c.id) ? p.concat(c.name) : p, []).sort((a, b) => a.localeCompare(b));

console.log(expectedResult);

Upvotes: 0

Shyam Tayal
Shyam Tayal

Reputation: 486

You can try this as well

allBoats.filter(entry => allowedIds.includes(entry.id)).map(item => item.name).sort()

Upvotes: 0

dangarfield
dangarfield

Reputation: 2330

const allowedIds = [1, 3]

const allBoats = [{
  id: 1,
  name: 'titanic'
}, {
  id: 2,
  name: 'anna'
}, {
  id: 3,
  name: 'boaty McBoatface'
}, ]

const result = allBoats
  .filter(b => allowedIds.includes(b.id))
  .map(b => b.name)
  .sort((a, b) => a.localeCompare(b))
console.log('result', result)

Upvotes: 2

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