CODEWITHSUNDEEP
pythonlualupa
silly_face_
silly_face_

Reputation: 11

how do you set up Lupa to restrict access to any Python objects/function from within Lua code?

I want to run user submitted Lua code within Python using Lupa. To do this safely, I want to sandbox the Lua code at source-code level. So far, I've managed to prevent the user-supplied code from accessing any dangerous Lua functions.

Now, I want to restrict the user-supplied Lua code from accessing any Python objects/functions.

I've tried to create an attribute_filter that always raises an AttributeError:

def filter_attribute_access(obj, attr_name, is_setting):
    raise AttributeError('access denied')

and initialized the LuaRuntime as follows:

lua_no_py = lupa.LuaRuntime(
    register_eval=False,
    attribute_filter=filter_attribute_access)

But I can still use Python functions, including built in ones:

obj = [1, 2, 3]
lua_func = lua_no_py.eval('function(py_obj) return python.iter(py_obj) end')
res = lua_func(obj)
print(res)

How can you prevent user-supplied code from accessing any Python code? And how do you test that it's successful?

Upvotes: 0

Views: 238

Answers (1)

Ника
Ника

Reputation: 1

Make a first eval with this:

_G.python = nil

Upvotes: 0

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