CODEWITHSUNDEEP
sed
Lolo
Lolo

Reputation: 4169

Partial duplication of a line with sed

How can I use sed to duplicate part of a string?

hello foo(ignore this);
hello bar(or that);
hello func(or anything really);

with

hello foo(x) foo(y)
hello bar(x) bar(y)
hello func(x) func(y)

I know I can use & multiple times in the replace statement of sed but I have trouble having the matching pattern & be only what's between hello and (

Upvotes: 1

Views: 50

Answers (3)

stevesliva
stevesliva

Reputation: 5665

I think you're on the right track with &:

sed 's/(.*/(/; s/[^ ]*(/&x) &y)/' test.txt
  • Clear out everything after open paren: s/(.*/(/
  • Then capture function name and open paren as & and repeat with x) and y): s/[^ ]*(/&x) &y)/
  • [^ ]* is capturing the string of non-space chars before the open paren

Upvotes: 2

sseLtaH
sseLtaH

Reputation: 11247

Using sed

$ sed -E 's/([^ ]* ([^(]*)).*/\1(x) \2(y)/' input_file
hello foo(x) foo(y)
hello bar(x) bar(y)
hello func(x) func(y)

Upvotes: 2

Lolo
Lolo

Reputation: 4169

My solution is really not pretty: I remove what I don't want from each line until I only have my function names and then I re-add what I did. I am sure there must be a more elegant approach:

$ more test.txt
hello foo(ignore this);
hello bar(or that);
hello func(or anything really);

$ more test.txt | sed  's/hello //g' | sed 's/(.*$//g' | sed 's/.*/hello &(x) &(y)/g'
hello foo(x) foo(y)
hello bar(x) bar(y)
hello func(x) func(y)

Upvotes: 1

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