CODEWITHSUNDEEP
pythonlistloopstuplespermutation
Thando
Thando

Reputation: 31

Storing The Output of a Permutation as a List of Lists

When I run the following code I get rows of tuples:

  {perm = itertools.permutations(['A','B','C','D','E','F'],4)

   for val in perm:
        print(val)}.

How do I make the code give me the output as a single list of lists instead of rows of tuples?

When I run the code I get something like this ('F', 'E', 'B', 'C') ('F', 'E', 'B', 'D') ('F', 'E', 'C', 'A') ('F', 'E', 'C', 'B')

type here

etc.

What I want is something like this

      [['F', 'E', 'B', 'C'],
       ['F', 'E', 'B', 'D'],
       ['F', 'E', 'C', 'A'],...,]

Upvotes: 0

Views: 37

Answers (1)

user20396240
user20396240

Reputation:

cast val into a list and append it to another list.

import itertools
perm = itertools.permutations(['A','B','C','D','E','F'],4)

result = []
for val in perm:
    result.append(list(val))

print(result)

The question is, do you want to generate all permutations and store them?

As you have it now, the generator will give you one permutation each time, which is memory efficient.

You can generate all of them into a list of lists, but just think if you really want that, since the number of permutations could be very large.

Upvotes: 0

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