CODEWITHSUNDEEP
python
Z-0
Z-0

Reputation: 1

function that checks if a number is a float

I currently have this how can I get it so it checks for a float and uses a while loop

def get_float():
    number = input('Input a decimal number ')
    while number != float:
        print('bad input ')
        number = input('Input a decimal number ')
    else:
        return number
        
get_float()

right now even if I enter a decimal number it says bad input and asks for another input

Upvotes: 0

Views: 209

Answers (3)

Z-0
Z-0

Reputation: 1

figured it out:

def get_float():
    while True:
        number = input('Input a decimal number ')
        try:
            if "." in number:
                floatnumber = float(number)
                print(floatnumber)
                break
            else:
                print("invalid number")
        except ValueError as err:
            print(err)
                
        
get_float()

Upvotes: 0

John Gordon
John Gordon

Reputation: 33351

number = input('Input a decimal number ')
while number != float:

This is wrong for a few reasons.

First, input() returns a string, so number is a string. It is not a floating point value.

Second, even if number were a proper floating point value, it is not equal to float, because float is a type object.

It seems like you really meant if type(number) != float. (But again, that would always be false here, because number is a string.)

Upvotes: 0

Silvio Mayolo
Silvio Mayolo

Reputation: 70377

Sometimes it's better to ask for forgiveness than permission.

def get_float():
    while True:
        number = input('Input a number ')
        try:
            return float(number)
        except ValueError:
            print('\n bad input\n ')

Upvotes: 3

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