Reputation:
For example I would like to have:
a
. . .
z
aa
ab
. . .
az
bz
. . .
zz
aaa
and so on.
Currently I'm here but I am lost. So feel free to propose a completely different solution.
count = 0
string = ''
for i in range(100):
count += 1
if i % 26 == 0:
count = 0
string += 'a'
ch = 'a'
x = chr(ord(ch) + count)
string = string[:-1] + x
print(i + 1, string)
and my output is something like this:
1 a
2 b
. . .
26 z
27 za
28 zb
. . .
52 zz
53 zza
54 zzb
. . .
Upvotes: 0
Views: 105
Reputation: 7858
Using more of standard library:
import itertools
import string
for i in range(1, 3): # Print items of length 1 and 2
for prod in itertools.product(string.ascii_lowercase, repeat=i):
print(''.join(prod))
What you describe is a sorted output of n-th powers of set {'a'...'z'}
in terms of cartesian products in string format (cartesian power n
of a set X
is, from a simple point of view, a set of all possible tuples (x_1, ..., x_n)
where all x_i
are contained in X
). itertools.product
implements exactly cartesian product and outputs in order of presence, so just loop over them. string.ascii_lowercase
is a simple string containing all letters a..z
in natural order. This is fast (uses C implementation of itertools
).
Upvotes: 2
Reputation: 632
Maybe try something like the following:
range(97,123) simply creates a range of numbers from 97 to 122, which converted to ASCII equates to a...z (done using chr())
So all our FUnction does, is it recieves a base string (starts with empty), prints out the base + range of charachters and calls its self with base + every charachter as the new base and depth decremented by 1
def printcharachters(base, depth):
if depth > 0:
for a in range(97, 123):
print(base + chr(a))
for a in range(97, 123):
printcharachters(base + chr(a), depth - 1)
printcharachters("", 2)
Replace the depth with your desired depth (for 2 the last string would be zz for 4 it would be zzzz).
Upvotes: 2