Reputation: 4686
Hi I am doing one checkscript with jquery and php I have written this :
$.post("chatController.php", {
ssha:"<?php echo $sechs1;?>",
user: "<?php echo $_SESSION["username"];?>",
class:1
}, function(data){
$.each(data, alert(this));
}, "json");
And from the PHP file I get something like :
echo json_encode(array("John","2pm"));
This array can have 0,1,2....unlimitied entries.. How I alert each of this entrie one by one ?
Perhaps something like:
For each data > alert(this)
Upvotes: 0
Views: 218
Reputation: 21449
to have proper json you must have key value pairs in your php array, something like:
json_encode(array("name"=>"John","time"=>"2pm"));
to list all object properties you can do:
for(var prop in data){
if(data.hasOwnProperty(prop)){ // this prevents inherited properties
console.log(prop);
}
}
Upvotes: 1
Reputation: 816600
You are calling alert
immediately and passing its return value to $.each
. You have to pass a function reference instead:
$.each(data, function(index, item){
alert(item);
});
Be careful with using class
as property name. It is a reserved keyword and you could have problems with it in browsers. Either put it in a string:
'class': 1
or rename it.
Upvotes: 3