CODEWITHSUNDEEP
c++linuxg++
MarcosP
MarcosP

Reputation: 5

warning: ISO C++ does not allow C99 designated initializers, what should i use instead?

I will simplify the problem to be more concrete. Compiling my c++ program with g++ and the -pedantic argument like this:

g++ -Wall -pedantic main.cpp

Gives me the following warning:

warning: ISO C++ does not allow C99 designated initializers [-Wpedantic]

This is what I am trying to implement:

typedef enum {
  ARG_HELP_LONG,
  ARG_HELP_SHORT,
} arg_t;

static const char *valid_args[] = {[ARG_HELP_LONG] = "--help",
                                   [ARG_HELP_SHORT] = "-h",
}

So that I can compare it to something else:

 if (strcmp(argv[i], valid_args[ARG_HELP_LONG]) == 0 || strcmp(argv[i], valid_args[ARG_HELP_SHORT]) == 0) {
    do something..
}

What should I use instead?

Also I get a warning telling me that I am not using valid_args, but I do use it. Is there any way of fixing this? Is it related to the above warning?

Upvotes: 0

Views: 1259

Answers (1)

463035818_is_not_an_ai
463035818_is_not_an_ai

Reputation: 122133

Just do not use the designated initialization of the array:

static const char *valid_args[] = {"--help","-h"};

Indices of the two elements are 0 and 1, respectively. The same as with the designated initializers, because the value of ARG_HELP_LONG and ARG_HELP_SHORT are 0 and 1, respectively.

C++ has designated initializers since C++20, though (from cppreference):

Note: out-of-order designated initialization, nested designated initialization, mixing of designated initializers and regular initializers, and designated initialization of arrays are all supported in the C programming language, but are not allowed in C++.

Upvotes: 2

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