Reputation: 363
I want to open the Settings-> Wireless & networks directly from my application.
How can I do that?
Upvotes: 33
Views: 46187
Reputation: 1
This work for me, kotlin in 2022.
val context = LocalContext.current
fun onEnableConnection() {
startActivity(context, Intent(Settings.ACTION_WIFI_SETTINGS), null) }
Upvotes: 0
Reputation: 2628
i tried solutions above and it give me error that if you want to open external open you should flag that intent with FLAG_ACTIVITY_NEW_TASK
here is my solution in kotlin
val intent = Intent(Settings.ACTION_WIFI_SETTINGS)
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
startActivity(getApplication(), intent, null)
Upvotes: 0
Reputation: 35
Use Following Function For Open WI_FI Settings
private void openWifi() {
Intent intent = new Intent(Settings.ACTION_WIRELESS_SETTINGS);
startActivity(intent);
}
Upvotes: 1
Reputation: 365
That code works for me.
startActivity(new Intent(android.provider.Settings.ACTION_WIFI_SETTINGS));
Upvotes: 12
Reputation: 171
You can access the WiFi settings directly using this:
Intent intent = new Intent(Intent.ACTION_MAIN);
intent.setClassName("com.android.settings", "com.android.settings.wifi.WifiSettings");
startActivity(intent);
The above did not work on Android 3.0, so I ended up using:
Intent intent = new Intent(Settings.ACTION_WIRELESS_SETTINGS);
startActivity(intent);
Upvotes: 17
Reputation: 6037
use the below code to call wireless and networks directly from your application.
Intent intent=new Intent();
intent.setComponent(new ComponentName("com.android.settings", "com.android.settings.WirelessSettings"));
startActivity(intent);
Upvotes: 2
Reputation: 8225
Try this:
startActivity(new Intent(android.provider.Settings.ACTION_WIRELESS_SETTINGS));
Or perhaps startActivityForResult. Your call. You can open different settings by checking the constants in Settings
Upvotes: 90