CODEWITHSUNDEEP
c#methods
AllAboutProgramming
AllAboutProgramming

Reputation: 7

How to multiply correctly two numbers in a method?

{
    Console.ForegroundColor= ConsoleColor.Yellow;
    Console.BackgroundColor = ConsoleColor.DarkRed;
    Console.Clear();
    Console.WriteLine("Please enter your name and I will tell you how many letters your name has!");
    string name = Console.ReadLine();
    Count(name);
    Console.WriteLine("Now tell me two numbers and I will multiply them!");
    Console.Read();

    try
    {
        Multiply();
    }
    catch (FormatException)
    {
        Console.WriteLine("You must enter a number!");
    }
}

public static void Count(string name)
{
    Console.WriteLine("Your name has {0} letters!", name.Length);
}

public static void Multiply()
{

    string firstNum = Console.ReadLine();
    string secondNum = Console.ReadLine();
    int num = Int32.Parse(firstNum);
    int num1 = Int32.Parse(secondNum);
    int result = num * num1;
    Console.WriteLine("The result is {0}", result);
}

Im a beginner and Im learning about methods so I made this simple code where the user should enter two numbers and I should multiply them, the problem is, whenever I enter two random numbers, I am getting some completely different numbers back no matter if i want to add them, multiply them or something third.

I cannot figure out why the "num1 * num2;" is not giving me a correct number. E.G. 54*19 should give me 1026, but instead its giving me -15.

Upvotes: 1

Views: 101

Answers (1)

Vivek Nuna
Vivek Nuna

Reputation: 1

you need to comment on the Console.Read(); line. this is the main cause.

I have run your code by commenting on the above line and it works as expected for me

Also, you need to handle the scenarios when the user can enter a non-integer input, so you could use int.TryParse for the same.

Also, try to handle the scenario where the integer value is very large and the multiplication of two numbers exceeds the integer max value.

Upvotes: 2

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