CODEWITHSUNDEEP
pythonnlpsequencesentencedifflib
k_p
k_p

Reputation: 313

Match the content of sentence/sequence in python

Suppose we 2 sequence of words

sentence1 = 'Ram is eating'

sentence2 = 'is Ram  eating'

sentence3 = 'is Ram playing'

sentence4 = 'movie Ram watching is'

how to get match% of such 2 sequences . difflib sequenceMatcher matches letter by letter . Any way to find match % in these cases.

match% between sentence1 and sentence2 = 3/3 i.e. 100%

match% between sentence1 and sentence3 = 2/3 i.e. 66.66%

match% between sentence1 and sentence4 = 2/3 i.e. 66.66%

match% = (number of words matching in sentence1 and sentence2 irrespective of position/total number of words in sentence1)*100

Upvotes: 0

Views: 97

Answers (1)

Bhargav
Bhargav

Reputation: 4286

How about converting string to list and find matching percentage.

sentence1 = 'Ram is eating'
sentence2 = 'is Ram  eating'

sentence1 = sentence1.split()
sentence2 = sentence2.split()

longest = max(sentence1, sentence2, key=len)

per = len(set(sentence1) & set(sentence2))  
result = per/len(longest)
print (f'{result *100}% matched')

Gives #

100.0% matched

Case 2

sentence1 = 'Ram is eating' 
sentence2 = 'is Ram'

sentence1 = sentence1.split()
sentence2 = sentence2.split()
longest = max(sentence1, sentence2, key=len)

per = len(set(sentence1) & set(sentence2))
result = per/len(longest)
print (f'{result *100}% matched')

Gives #

66.66666666666666% matched

Case 3

sentence1 = 'Ram is eating'

sentence2 = 'is Ram'
sentence3 = 'is Ram playing'

sentence1 = sentence1.split()
sentence2 = sentence2.split()
sentence3 = sentence3.split()


longest = max(sentence1, sentence3, key=len)

per = len(set(sentence1) & set(sentence3)) 
result = per/len(longest)
print (f'{result *100}% matched')

Gives #

66.66666666666666% matched

Upvotes: 0

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