Reputation: 11
complete bash noob here. Had the following command (1.) and it worked as expected but it seemed a bit naive for what I needed:
cat users.txt | tee >(cut -f 1 >> cut_out.txt) >(cut -f 2 >> cut_out.txt) >(cut -f 3 >> cut_out.txt) >(cut -f 4 >> cut_out.txt)
Output:
W Humphrey
SummersW
FoxxR
noreply
DaibaN
PeanutbutterM
PetersJ
DaviesJ
BlaireJ
GongoH
MurphyF
JeffersD
HorsemanB
...
cat users.txt | for i in {1..4}; do cut -f $i >> cut_out.txt; done
Output:
HumphreyW
The command above only returned a single word from the list and some white-space.
for i in {1..4}; do cat users.txt | cut -f $i >> cut_out.txt; done
Have a solution, more-so wanted an explanation because I am dumb and still learning about I/O in bash. Cheers.
Upvotes: 1
Views: 47
Reputation: 189487
If the order of the output is unimportant, and there are only four coumns in the file, simply
tr '\t' '\n' <users.txt >cut_out.txt
If you only want the first four columns in any order,
cut -f1-4 users.txt |
rt '\t' '\n' >cut_out.txt
(Thanks to @KamilCuk for raising this in a comment.)
Otherwise your third attempt is basically fine, though you want to avoid the useless cat
and redirect only once;
for i in {1..4}; do
cut -f "$i" users.txt
done > cut_out.txt
This is obviously less efficient than only reading the file once. If the file is small enough to fit into memory, you could write a simple Awk script to read it once and split it up into variables, and then write out these variables in the order you want.
The second attempt is wrong because cat
only supplies a single instance of the data to the pipe, and the first iteration of the loop consumes it all.
Upvotes: 1
Reputation: 17075
Just a remark
awk -F '[\t]' '{for(i = 1; i <= 4; i++) print $i}' users.txt > cut_out.txt
Is basically what your cat ... | tee >(cut ...) ...
does.
Upvotes: 1