CODEWITHSUNDEEP
python
dafukdidijustcode
dafukdidijustcode

Reputation: 11

How to print 'x' if the input int is b/w the desired numbers in python?

So, I started making a program and now I require it to print anything I like if the number is between 1-100, How to I make the program realize that it needs to print it if the number's between 90 and 100?

#This is a sample code
F2 = int(input())
if F2 == range(90 , 100):
    print("A")
else:
    print("BRUH")

I'm really new to this, I'll be very thankful if someone could help me

Upvotes: 1

Views: 336

Answers (3)

Arifa Chan
Arifa Chan

Reputation: 1017

Use in operator for membership test. == is comparison operator for equality.

print("A" if (F2 := int(input())) in range(90,101) else "BRUH")

Upvotes: 1

raiyan22
raiyan22

Reputation: 1179

Simply do an if else check and if it falls under the range of 90 to 100 then it will print.

#This is a sample code
F2 = int(input())
if F2 >=90 and F2 <=100:
    print("A")
else:
    print("BRUH")

Upvotes: 1

solac34
solac34

Reputation: 168

You're checking if f2 is equal to range(90,100), correct form is if it's IN the range(90,100).

if F2 in range(90,101): #last number is not included in range(101 won't be included)
    print('A')

also, if you try

f2 = range(90,100)
print(f2)

you'll understand what f2 == range(90,100) means.

if you use in, code will check if f2 in [90,91,92...100] , if f2 will be equal any of them, then returns True.

Upvotes: 2

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