CODEWITHSUNDEEP
python
user1234Es
user1234Es

Reputation: 1

I am trying to print a statement that will show any number that is great than 5

I am trying to print any number that is great than n, which is 5 in this case. It is only printing 6 and 7. I am not sure what I am doing wrong. This is my code. I am looping through the array and testing if i is greater then n (5)

list = [2, 3, 4, 5, 6, 7, 8, 9]
n = 5
filter_list (list, n)

def filter_list (list, n):
` `for i in range(len(list)):
` `if list[i] > n:
` `print (list[i])

the outcome is only 6, 7. Its not 6, 7, 8, 9 which is what I would like it

It doesnt print the desired outcome

Upvotes: 0

Views: 44

Answers (3)

hafshahfitri
hafshahfitri

Reputation: 39

Your code is working if you give indent before if statement

list = [2, 3, 4, 5, 6, 7, 8, 9]
n = 5

def filter_list (list, n):
    for i in range(len(list)):
        if list[i] > n:
            print (list[i])

filter_list (list, n)

Or you can try this code :

list1 = [2, 3, 4, 5, 6, 7, 8, 9]
n = 5

for i in list1 :
    if i > n:
        print(I)

Hope this will help you :)

Upvotes: 1

user20603322
user20603322

Reputation:

Your code is completely fine, if you fix your intent.

list = [2, 3, 4, 5, 6, 7, 8, 9]
n = 5


def filter_list (list, n):
    for i in range(len(list)):
        if list[i] > n:
            print (list[i],end =' ')

print(filter_list (list, n))

Output: 6 7 8 9

And you don’t need to call a function. If we use list compression we can increase speed and code readability 👩‍💻

list = [2, 3, 4, 5, 6, 7, 8, 9]

n = 5

print(list(i for i in List if i > n))

Upvotes: 0

Bhargav
Bhargav

Reputation: 4092

For me your code working fine just fix the indent. Just adding end '' at print to print on same line.

list = [2, 3, 4, 5, 6, 7, 8, 9]
n = 5


def filter_list (list, n):
    for i in range(len(list)):
        if list[i] > n:
            print (list[i],end =' ')
        
filter_list (list, n)

Gives #

6 7 8 9

Upvotes: 0

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