CODEWITHSUNDEEP
ckernighan-and-ritchie
Emryss
Emryss

Reputation: 13

Stumped by K&R exercise 1.5.2

I am currently trying to learn C by using the K&R, but I am completely stumped by example 1.5.2. For some reason, after I press Ctrl-Z, instead of printing nc, it prints nc multiplied by 2. I don't know what could be causing this problem (I copied the code exactly how it is in the book). The compiler I am using is Visual Studio 2010. Here is the code:

#include <stdio.h>

main()
{

long nc;

nc = 0;
while (getchar() != EOF)
    ++nc;
printf("%1d\n", nc);


}

Upvotes: 1

Views: 407

Answers (3)

Brian Roach
Brian Roach

Reputation: 76918

Because enter is a keystroke.

If your input is:

1<enter>
1<enter>
1<enter>
^z

it would output:

6

Upvotes: 2

Roshan Mathews
Roshan Mathews

Reputation: 5898

Could not reproduce your error. I added some debugging statements, 

#include <stdio.h>

main() {
     int nc = 0, ch;

     while ((ch = getchar()) != EOF) {
          printf("%d\n", ch);
          ++nc;
     }
     printf("nc - %1d\n", nc);


}

And then tried it with gcc on Windows:

E:\temp>gcc eof.c

E:\temp>a
^Z
nc - 0

E:\temp>a
foo bar
102
111
111
32
98
97
114
10
^Z
nc - 8

And then with Visual Studio 2008:

E:\temp>cl eof.c
Microsoft (R) 32-bit C/C++ Optimizing Compiler Version 15.00.30729.01 for 80x86
Copyright (C) Microsoft Corporation.  All rights reserved.

eof.c
Microsoft (R) Incremental Linker Version 9.00.30729.01
Copyright (C) Microsoft Corporation.  All rights reserved.

/out:eof.exe
eof.obj

E:\temp>eof
^Z
nc - 0

E:\temp>eof
foo bar
102
111
111
32
98
97
114
10
^Z
nc - 8

Upvotes: 0

Tom
Tom

Reputation: 44881

Not sure why you get the behaviour you describe but that should be %ld not %1d

Upvotes: 1

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