CODEWITHSUNDEEP
bashenvironment-variablesshzsh
xeruf
xeruf

Reputation: 3010

Make ZSH pass a variable as space-delimited parameters

I would like to create an alias that works in zsh and bash, but weirdly enough zsh tries to pass on an unquoted variable as a single argument:

❯ zsh -f
grasshopper% LS_OPTIONS="-l -a" && ls $LS_OPTIONS
ls: invalid option -- ' '
Try 'ls --help' for more information.
grasshopper% bash --norc
bash-5.1$ LS_OPTIONS="-l -a" && ls $LS_OPTIONS
total 0
drwxr-xr-x  2 janekf janekf   40 28. Nov 14:02 .
drwxrwxrwt 24 root   root   2400 28. Nov 16:41 ..

Is there a option to stop that?

See also Using variables as command arguments in zsh, but the answer there is zsh-specific.

Upvotes: 2

Views: 643

Answers (2)

user1934428
user1934428

Reputation: 22366

Your LS_OPTIONS will be passed as a single parameter to ls, and of course ls can not handle it.

In zsh, define your alias as

 alias ls='ls ${(z)LS_OPTIONS}'

The (z) causes the value to be split on white space and passed as individual arguments to ls.

Upvotes: 2

chepner
chepner

Reputation: 532418

If you want something that works in both zsh and bash, use an array.

LS_OPTIONS=(-l -a) && ls "${LS_OPTIONS[@]}"

You can set the SH_WORD_SPLIT option in zsh to make parameter expansions undergo word-splitting just as in bash, but unquoted expansions in bash are subject to pathname expansion as well, so I don't recommend their use.

Upvotes: 5

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