How to add delay between loop python?

Question

i want to ask , i try with my coding but it still not working, i want to execute 2 loop with delay and print each word with delay.

here my coding

import threading,time

def func_name1():
fruits = ["apple", "banana", "cherry"]
for i in fruits:
    time.sleep(2)
    print(i)

def func_name2():
fruits2 = ["1", "2", "3"]
for i in fruits2:
    time.sleep(2)
    print(i)

f1 = threading.Thread(target=func_name1)
f2 = threading.Thread(target=func_name2)
f1.start()
time.sleep(2)
f2.start()

output like this

apple
1
banana
2
cherry
3

i want scenario like this

Answer 1

Try this.

I have updated my code Now it matches your scenario. The whole Script takes approximatly 25.03 seconds.

def func_name1():
    fruits = ["apple", "banana", "cherry"]
    a = 0
    for i in fruits:
        a += 1
        print(i)
        if a == len(fruits):
            return
        time.sleep(10)

def func_name2():
    fruits2 = ["1", "2", "3"]
    a = 0
    for i in fruits2:
        a +=1
        print(i)
        if a==len(fruits2):
            return
        time.sleep(10)

f1 = threading.Thread(target=func_name1)
f2 = threading.Thread(target=func_name2)
f1.start()
time.sleep(5)
f2.start()

apple
1
banana
2
cherry
3

---

To check the whole execution time. Use this code.

import threading,time

t = time.time()

def func_name1():
    fruits = ["apple", "banana", "cherry"]
    a = 0
    for i in fruits:
        a += 1
        print(i)
        if a == len(fruits):
            return
        time.sleep(10)

def func_name2():
    fruits2 = ["1", "2", "3"]
    a = 0
    for i in fruits2:
        a +=1
        print(i)
        if a==len(fruits2):
            return
        time.sleep(10)

f1 = threading.Thread(target=func_name1)
f2 = threading.Thread(target=func_name2)
f1.start()
time.sleep(5)
f2.start()

f2.join()

print(time.time() - t)