CODEWITHSUNDEEP
python
AwayB
AwayB

Reputation: 9

Print output includes 'None'

def backwards_alphabet(curr_letter):
    if curr_letter == 'a':
        print(curr_letter)
    else:
        print(curr_letter)
        prev_letter = chr(ord(curr_letter) - 1)
        backwards_alphabet(prev_letter)

starting_letter = input()

print (backwards_alphabet(starting_letter)) #this is the code i wrote

The output includes "None" but I have no idea why. Image of output

Upvotes: 0

Views: 94

Answers (1)

scotscotmcc
scotscotmcc

Reputation: 3113

The function print takes a parameter - you are giving it the result of backwards_alphabet(starting_letter).

Since you aren't explicit about what backwards_alphabet() returns - which you do would with by including return 'this is what I am returning', it will return None by default.

So, you are calling print(None) and it prints 'None'.

Since your function backwards_alphabet() already has all of the printing within it, you don't want to do print(backwards_alphabet(...)), you just want to call backwards_alphabet(...) by itself.

Upvotes: 1

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