Reputation: 43523
Currently I have a byte[]
that contains all the data of an image file, just want to build an instance of HttpPostedFileBase
so that I can use an existing method, instead of creating a new overload one.
public ActionResult Save(HttpPostedFileBase file)
public ActionResult Save(byte[] data)
{
//Hope I can construct an instance of HttpPostedFileBase here and then
return Save(file);
//instead of writing a lot of similar codes
}
Upvotes: 30
Views: 24991
Reputation: 35146
Create a derived class as follows:
class MemoryFile : HttpPostedFileBase
{
Stream stream;
string contentType;
string fileName;
public MemoryFile(Stream stream, string contentType, string fileName)
{
this.stream = stream;
this.contentType = contentType;
this.fileName = fileName;
}
public override int ContentLength
{
get { return (int)stream.Length; }
}
public override string ContentType
{
get { return contentType; }
}
public override string FileName
{
get { return fileName; }
}
public override Stream InputStream
{
get { return stream; }
}
public override void SaveAs(string filename)
{
using (var file = File.Open(filename, FileMode.CreateNew))
stream.CopyTo(file);
}
}
Now you can pass instance of this class where HttpPostedFileBase is expected.
Upvotes: 54
Reputation: 1039238
You cannot manually create an instance of HttpPostedFileBase
or derived classes (HttpPostedFile
). This class is only supposed to be instantiated by the framework. Why don't you get rid of the second controller action that takes a byte array? It's not necessary. The default model binder will work fine with the one taking a HttpPostedFileBase
.
Upvotes: 1