Reputation: 92
I'm trying to set artist information via variables with spaces in them. Lame craps out. Maybe I'm being retarded with bash?
#!/bin/bash
year=2008;
artist="New Kids On The Block";
album="The Block";
bitrate=320;
lame="lame -b $bitrate --ta \"$artist\" --tl \"$album\" --ty $year"
function first_half
{
for (( i=1;i<10;i++ )); do
$lame "track_0$i.wav" "track_0$i.mp3";
done;
}
function second_half
{
for (( x=10;x<18;x++ )); do
echo $lame "track_$x.wav" "track_$x.mp3";
done;
}
first_half &
first_pid=$!
#second_half &
#second_pid=$
Here's the output of the script.
user@host:~/ogg/noartist/unknown_disc$ ./encode.sh
user@host:~/ogg/noartist/unknown_disc$ lame: excess arg The
lame: excess arg The
Lame complains for each loop iteration... of course.
I changed the script to echo out one of the iterations of the loop and this is what is outputted.
lame -b 320 --ta "New Kids On The Block" --tl "The Block" --ty 2008 track_01.wav track_01.mp3
This works line fine on the shell... I'm confused. What am I doing wrong here? I know it has to do with the spaces in my variables, but I'm not sure how to fix it.
Upvotes: 2
Views: 3603
Reputation: 5821
"lame" should be a function. Note: I ran "lame" in the same directory, "./lame", so I could use another script to test the results.
#!/bin/bash
year=2008
artist="New Kids On The Block"
album="The Block"
bitrate=320
function lame()
{
#local bitrate=$1
#local artist=$2
#local album=$3
#local year=$4
local in=$1
local out=$2
./lame -b "$bitrate" --ta "$artist" --tl "$album" --ty "$year" "$in" "$out"
}
function first_half
{
for (( i=1;i<10;i++ )); do
lame "track_0$i.wav" "track_0$i.mp3"
done
}
first_half &
first_pid=$!
lame:
#!/bin/bash
echo ===============================================
echo $0 $*
echo "0 ==> \"$0\""
CNT=1
while true; do
echo -n "$CNT "
[ $CNT -lt 10 ] && echo -n " "
echo "==> \"$1\""
CNT=$(($CNT + 1))
shift
[ -z "$1" ] && break
done
echo ===============================================
Sample output (partial):
===============================================
./lame -b 320 --ta New Kids On The Block --tl The Block --ty 2008 track_01.wav track_01.mp3
0 ==> "./lame"
1 ==> "-b"
2 ==> "320"
3 ==> "--ta"
4 ==> "New Kids On The Block"
5 ==> "--tl"
6 ==> "The Block"
7 ==> "--ty"
8 ==> "2008"
9 ==> "track_01.wav"
10 ==> "track_01.mp3"
===============================================
===============================================
./lame -b 320 --ta New Kids On The Block --tl The Block --ty 2008 track_02.wav track_02.mp3
0 ==> "./lame"
1 ==> "-b"
2 ==> "320"
3 ==> "--ta"
4 ==> "New Kids On The Block"
5 ==> "--tl"
6 ==> "The Block"
7 ==> "--ty"
8 ==> "2008"
9 ==> "track_02.wav"
10 ==> "track_02.mp3"
===============================================
Upvotes: 1
Reputation: 28258
The problem is the line
lame="lame -b $bitrate --ta \"$artist\" --tl \"$album\" --ty $year"
because $lame later is evaluated more than once. You can run
bash -xv ./encode.sh
to see commands executed and variables substituted (instead of running "bash -xv" you can add "set -xv" inside the script).
Upvotes: 1
Reputation: 92
I found a temporary solution that I used...
It's a bit of a hack, but it does the job:
#!/bin/bash
year="2008";
artist="\"New Kids On The Block\"";
album="\"The Block\"";
bitrate=320;
genre="Pop";
lame="lame -b $bitrate --ta $artist --tl $album --ty $year --tg $genre"
function first_half
{
echo "Encoding first half...";
for (( i=1;i<10;i++ )); do
echo $lame "track_0$i.wav" "track_0$i.mp3" > run1.sh;
bash run1.sh >/dev/null 2>/dev/null;
done;
rm -f run1.sh;
}
function second_half
{
echo "Encoding second half too...";
for (( x=10;x<18;x++ )); do
echo $lame "track_$x.wav" "track_$x.mp3" >run2.sh;
bash run2.sh >/dev/null 2>/dev/null;
done;
rm -f run2.sh;
}
first_half &
echo $! > first_half.pid
second_half
echo $! > second_half.pid
echo "Done!";
rm *.pid -f
Upvotes: 0