Reputation:
I have a column with pairs like these
id | pairs |
---|---|
1 | a,b,c |
2 | b,d |
3 | a |
4 | d,e |
5 | g,h |
6 | a,h |
7 | f,d |
8 | o,p |
I want to have these output
[('ca', 'b'), ('a', 'c'),('b','c'),('b','d'),('d','e'),('g','h'),('a','h'),('f','d'),('o','p')]
I did these, but not the desired solution
for pair in combinations([df['pairs']], 2):
print(pairs)
any suggestions?
Upvotes: 1
Views: 112
Reputation: 461
try this
pairs = []
for row in df['pairs']:
row_list = row.split(',')
for pair in combinations(row_list, 2):
pairs.append(pair)
print(pairs)
Upvotes: 1