Reputation: 11
I have to print nth prime palindrome number with the help of this program, where n is number given by the user but I have a problem in this program, as it is taking much time to print the answer.
n=int(input())
l=[]
for i in range(1,1000000):
y=True
if str(i)==str(i)[::-1]:
if i>=2:
for j in range(2,i):
if i%j==0:
y=False
break
if y:
l.append(i)
print("Your Prime Palindrome Number Is:",l[n-1])
How can I make this code time efficient?
Upvotes: 0
Views: 567
Reputation: 27105
The first part of this code is not specific to this question. It's a general purpose strategy for testing prime numbers. It's faster than sympy.isprime() for values lower than ~500,000 (Python 3.11.1 on Intel Xeon) after which the sympy version betters this implementation.
from math import sqrt, floor
def isprime(n):
if n < 2:
return False
if n == 2 or n == 3:
return True
if n % 2 == 0 or n % 3 == 0:
return False
for i in range(5, floor(sqrt(n))+1, 6):
if n % i == 0 or n % (i + 2) == 0:
return False
return True
Now you need something to test for a palindrome. This function will return True if the string representation of the object is palindromic.
def ispalindrome(o):
return (_ := str(o)) == _[::-1]
And this is the main part of the program. As 2 is the only even prime number, let's treat that as a special case. Otherwise start with 3 and just test subsequent odd numbers.
N = int(input('Enter value for N: '))
if N > 0:
if N == 1:
print(2)
else:
p = 3
while True:
if isprime(p) and ispalindrome(p):
if (N := N - 1) == 1:
print(p)
break
p += 2
Sample output:
Enter value for N: 11
313
Upvotes: 1